欢迎访问ic37.com |
会员登录 免费注册
发布采购

SA2005PPA 参数 Datasheet PDF下载

SA2005PPA图片预览
型号: SA2005PPA
PDF下载: 下载PDF文件 查看货源
内容描述: [Analog Circuit]
分类和应用:
文件页数/大小: 16 页 / 375 K
品牌: A1PROS [ A1 PROS CO., LTD. ]
 浏览型号SA2005PPA的Datasheet PDF文件第8页浏览型号SA2005PPA的Datasheet PDF文件第9页浏览型号SA2005PPA的Datasheet PDF文件第10页浏览型号SA2005PPA的Datasheet PDF文件第11页浏览型号SA2005PPA的Datasheet PDF文件第13页浏览型号SA2005PPA的Datasheet PDF文件第14页浏览型号SA2005PPA的Datasheet PDF文件第15页浏览型号SA2005PPA的Datasheet PDF文件第16页  
SA2005P  
ssaammeess  
TYPICAL APPLICATION  
CALCULATION OF EXTERNAL RESISTOR VALUES  
In figure 8, all the components required for a three-phase  
power/energy metering section, is shown. The application  
uses current transformers for current sensing. The 4-wire  
meter section is capable of measuring 3x230V/80A with  
precision better than Class 1  
VoltageDivider  
The three voltage divider for voltage measurement are  
identical so resistor values for one phase will be calculated.  
The voltage divider is calculated for a voltage drop of 14V.  
Equationsforthevoltagedividerinfigure5are:  
RA = R16 + R19 + R22  
RB = R8 || R13  
The most important external components for the SA2005P  
integrated circuit are the current sense resistors, the voltage  
sense resistors as well as the bias setting resistor.  
Combiningthetwoequationsgives:  
Bias Resistor  
(RA + RB ) / 230V = RB / 14V  
Resistor values R11 = R12 = R13= 24kW and R8 =1MW is  
chosen.  
R7 defines all on-chip and reference currents. With R7=24kW,  
optimum conditions are set.  
CT Termination Resistor  
Substitutingthevaluesresultin:  
The voltage drop across the CT termination resistor at rated  
current should be at least 20mV. The CT's used have low  
phase shift and a ratio of 1:2500.The CT is terminated with a  
2.7W resistor giving a voltage drop across the termination  
resistor 864mV at rated conditions (Imax for the meter).  
RB = 23.4375kW  
RA = RB x (230V / 14V - 1)  
RA = 361.607kW.  
Resistor values of R16, R19 and R22 is chosen to be 130k,  
130kand100k.  
Current Sense Resistors  
The resistors R1 and R2 define the current level into the  
current sense inputs of phase one of the device. The resistor  
values are selected for an input current of 16µA on the current  
inputs at rated conditions.  
The three voltage channels are identical so R14= R15= R16 ,  
R17=R18=R19andR20=R21=R22.  
According to equation described in the Current Sense inputs  
section:  
R1 = R2 = ( I / 16µA ) x R / 2  
SH  
L
= 80A /2500 / 16µA x 2.7W / 2  
= 2.7kW  
I =Linecurrent/CTRatio  
L
The three current channels are identical so R1 = R2 = R3 = R4  
=R5=R6.  
12/16  
http://www.sames.co.za