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B048T240T30A 参数 Datasheet PDF下载

B048T240T30A图片预览
型号: B048T240T30A
PDF下载: 下载PDF文件 查看货源
内容描述: [BCM BUS CONVERTER 24V 300W]
分类和应用:
文件页数/大小: 18 页 / 2477 K
品牌: VICOR [ VICOR CORPORATION ]
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B048x240y30A  
Not Recommended for New Designs  
9.0 SINE AMPLITUDE CONVERTER™ POINT OF LOAD CONVERSION  
2000 pH  
IOUT  
LOUT = 600 pH  
ROUT  
LIN = 0.6 nH  
43.4 mΩ  
+
+
RCOUT  
417 µΩ  
RCIN  
0.006 Ω  
1/2 • VIN  
2.2mΩ  
V•I  
K
1/2 • IOUT  
+
C
IN  
2 µF  
C
12 µF  
+
OUT  
VOUT  
VIN  
IQ  
123 mA  
Figure 13 VI Chip® module AC model  
The Sine Amplitude Converter (SAC™) uses a high frequency  
resonant tank to move energy from input to output. (The  
ROUT represents the impedance of the SAC, and is a function of  
the RDSON of the input and output MOSFETs and the winding  
resistance of the power transformer. IQ represents the  
quiescent current of the SAC control, gate drive circuitry, and  
core losses.  
resonant tank is formed by Cr and leakage inductance Lr in the  
power transformer windings as shown in the BCM module  
Block Diagram. See Section 8). The resonant LC tank, operated  
at high frequency, is amplitude modulated as a function of  
input voltage and output current. A small amount of  
capacitance embedded in the input and output stages of the  
module is sufficient for full functionality and is key to achieving  
power density.  
The use of DC voltage transformation provides additional  
interesting attributes. Assuming that ROUT = 0 Ω and IQ = 0 A,  
Eq. (3) now becomes Eq. (1) and is essentially load  
independent, resistor R is now placed in series with VIN.  
The B048x240y30A SAC can be simplified into the preceeding  
model.  
At no load:  
R
SAC™  
VOUT  
+
K = 1/2  
VIN  
VOUT = VIN  
K
(1)  
(2)  
K represents the “turns ratio” of the SAC.  
Rearranging Eq (1):  
Figure 14 K = 1/2 Sine Amplitude Converter™  
VOUT  
K =  
with series input resistor  
VIN  
The relationship between VIN and VOUT becomes:  
VOUT = (VIN – IIN R) K  
(5)  
In the presence of load, VOUT is represented by:  
Substituting the simplified version of Eq. (4)  
(IQ is assumed = 0 A) into Eq. (5) yields:  
VOUT = VIN K – IOUT ROUT  
(3)  
(4)  
and IOUT is represented by:  
IIN – IQ  
2
VOUT = VIN K – IOUT R K  
(6)  
IOUT  
=
K
BCM® Bus Converter  
Page 11 of 18  
Rev 1.1  
vicorpower.com  
800 927.9474  
11/2014