ELM92xxxx CMOS 600kHz High output current PWM step-up DC/DC converter
Vce=Vout, L=2.2μH, Cout=47μF, D=MA735, Vss=0V, Top=25°C
Condition Min. Typ. Max. Unit Note
Vout=3.0V (ELM92302x)
Parameter
Input voltage
Starting voltage
Output voltage1
Symbol
Vin
7
0.9
V
V
V
Vst No-load
Vout1 Iout=60mA, Vin=1.5V
1
1
2.925 3.000 3.075
Vout1 Vout1 Vout1
×1.005 ×1.010 ×1.020
Output voltage2
Vout2 Iout=0.1mA, Vin=1.5V
V
1
Current consumption1
Current consumption2
Current consumption
in Shutdown
Oscillating frequency
Duty ratio
Iss1 Vout=Vout(T)×0.95
Iss2 Vout=Vout(T)+0.5V
300
75
480
120
μA
μA
2
2
Isd Vout=Vout(T)×0.95, Vce=0
0.5
μA
2
Fosc Vout=Vout(T)×0.95
Duty Vout=Vout(T)×0.95
510
80
600
88
690
95
kHz
%
3
3
Frequency of
Fimt
12
17
kHz
3
Intermittent control
On-resistance of LX switch
Ron Vout=Vout(T)×0.95
250
340
1
mΩ
μA
V
4
5
6
6
Leakage current of LX switch Ilxl Vout=Vlx=7V
CE Input voltage "H"
CE Input voltage "L"
Vceh
Vcel
0.8
0.25
0.1
V
Vout=Vout(T)×0.95,
Vce=Vout(T)×0.95
CE Input current "H"
Iceh
μA
μA
6
6
CE Input current "L"
Icel Vout=Vout(T)×0.95, Vce=0
-0.1
Vout : input voltage to VOUT pin
Vce : input voltage to CE pin
Vout(T) : typical value of Vout1
Remarks : test circuit No
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Vce=Vout, L=2.2μH, Cout=47μF, D=MA735, Vss=0V, Top=25°C
Condition Min. Typ. Max. Unit Note
Vout=3.3V (ELM92332x)
Parameter
Input voltage
Starting voltage
Output voltage1
Symbol
Vin
7
0.9
V
V
V
Vst No-load
Vout1 Iout=60mA, Vin=1.5V
1
1
3.218 3.300 3.382
Vout1 Vout1 Vout1
×1.005 ×1.010 ×1.020
Output voltage2
Vout2 Iout=0.1mA, Vin=1.5V
V
1
Current consumption1
Current consumption2
Current consumption
in Shutdown
Oscillating frequency
Duty ratio
Iss1 Vout=Vout(T)×0.95
Iss2 Vout=Vout(T)+0.5V
320
80
510
130
μA
μA
2
2
Isd Vout=Vout(T)×0.95, Vce=0
0.5
μA
2
Fosc Vout=Vout(T)×0.95
Duty Vout=Vout(T)×0.95
510
80
600
88
690
95
kHz
%
3
3
Frequency of
Fimt
12
17
kHz
3
Intermittent control
On-resistance of LX switch
Leakage current of LX switch
CE Input voltage "H"
CE Input voltage "L"
Ron Vout=Vout(T)×0.95
Ilxl Vout=Vlx=7V
Vceh
Vcel
245
330
1
mΩ
μA
V
4
5
6
6
0.8
0.25
0.1
V
Vout=Vout(T)×0.95,
CE Input current "H"
CE Input current "L"
Iceh
μA
μA
6
6
Vce=Vout(T)×0.95
Icel Vout=Vout(T)×0.95, Vce=0
-0.1
Vout : input voltage to VOUT pin
Vce : input voltage to CE pin
Vout(T) : typical value of Vout1
Remarks : test circuit No
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15 - 6
ELM-TECH [ ELM Technology Corporation ]
